1 条题解
- 
  0蠢方法(暴力) #include <bits/stdc++.h> using namespace std; const int N = 1e7 + 10; const int INF = 0x3f3f3f3f; int n; long long a[N],dpm[N],dpn[N],nmax = -INF,nmin = INF; int main(){ cin >> n; for(int i = 1;i <= n;i++){ cin >> a[i]; } dpn[0] = dpm[0] = 1; for(int i = 1;i <= n;i++){ dpm[i] = a[i]; dpm[i] = max(a[i],dpm[i - 1] * a[i]); dpn[i] = a[i]; dpn[i] = min(a[i],dpn[i - 1] * a[i]); dpm[i] = max(dpm[i],dpn[i - 1] * a[i]); dpn[i] = min(dpn[i],dpm[i - 1] * a[i]); //printf("dpm[%d] = %d\n",i,dpm[i]); //printf("dpn[%d] = %d\n",i,dpn[i]); nmax = max(nmax,dpm[i]); nmin = min(nmin,dpn[i]); } cout << nmax << endl << nmin; return 0; }
信息
- ID
- 1764
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 9
- 标签
- 递交数
- 98
- 已通过
- 9
- 上传者
