1行。

int main() { int a,b; __builtin_scanf("%d%d",&a,&b); __builtin_prinf("%d",a+b);

#include<bits/stdc++.h> using namespace std; const int N=1e3+10; int a,b; int main() { cin >> a >> b; cout << a+b; return 0; }

#include using namespace std; int main() { int a,b; cin>>a>>b; cout<<a+b; }

#include using namespace std; int main() { int a,b; cin>>a>>b; cout<<a+b;

}

#include using namespace std; int main() { int a , b;

cin>>a>>b;

cout<<a+b;

return 0;	

}

#include<iostream>
using namespace std;
int main(){
    int a,b;
    cin>>a>>b;
    cout<<a+b;
return 0;
}

谁不会这道题？？

#include<bits/stdc++.h>
using namespace std;
int main(){
    int a,b;
    cin>>a>>b;
    cout<<a+b;
    return 0;
}

其实是我不会

禁止发疯！！！

最短题解

#include<iostream>
int a,b;int main(){std::cin>>a>>b;std::cout<<a+b;}

#include<iostream>
using namespace std;
int main()
{
	int a,b;
	cin>>a>>b;
	cout<<a+b;
}

#include<iostream>
using namespace std;
int main(){
	int a,b,c;
	cin>>a>>b;
	c=a+b;
	cout<<c;
}

http://ybt.ssoier.cn:8088/problem_show.php?pid=1510

#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 10;
const int INF = 0x3f3f3f3f;

int T;
int r[30];//r[i]表示第i个时间点需要工作的人数 
int n;
int num[30] , x;//num[i]表示第i个时间点有多少人开始工作 
int L , R , ans; 
vector<pair<int,int> > vc[N];
int dis[N];
bool vis[N];
queue<int> q;
void spfa(int mid)//最长路 
{
	memset(dis, -INF , sizeof(dis));
	memset(vis , 0 , sizeof(vis));
	while(!q.empty()) q.pop();
	dis[0] = 0;
	vis[0] = 1;
	
	q.push(0);
	
	while(!q.empty())
	{
		int u = q.front();
		q.pop();
		if( u == 24 && dis[u] > mid)
			return;
		
		vis[u] = 0;
		for(int i = 0; i < vc[u].size(); i++)
		{
			int v = vc[u][i].first , w = vc[u][i].second;
			if(dis[v] < dis[u] + w)
			{
				dis[v] = dis[u] +w;
				if(!vis[v]) 
				{
					q.push(v);	
					vis[v] = 1;
				}
			}	
		} 
	}
}

bool check(int mid)//一共mid人工作 
{
	for(int i = 0; i <= 24; i++)
	{
		vc[i].clear();	
	}
	
	//隐藏不等式
	//sum[i] 从1点到i点需要工作的人数
	//	sum[i] - sum[i - 1] >= 0
	//	sum[i - 1] - sum[i] >= -num[i]
	for(int i = 1; i <= 24; i++)
	{
		vc[i - 1].push_back({i , 0});
		vc[i].push_back({i - 1 ,-num[i]});	
	} 
//	23 24 1 2 3 4 5 6 7 8 9
//	sum[i] - sum[i - 8] >= r[i]
	for(int i = 8; i <= 24; i++)
		vc[i - 8].push_back({i , r[i]});
	
//	sum[24] - sum[8] <= mid - r[i]; 
//	sum[i] - sum[i + 16] >= r[i] - mid;
	for(int i = 1; i <= 8; i++)
		vc[i + 16].push_back({i , r[i] - mid});
		
//	sum[24] - sum[0] <= mid
	vc[0].push_back({24,mid});
	vc[24].push_back({0, -mid});
	
	spfa(mid);
	return dis[24] == mid;
}

int main()
{
	cin >> T;
	while( T-- )
	{
		memset(num , 0 , sizeof(num));
		for(int i = 1; i <= 24; i++)
			cin >> r[i];
			
		cin >> n;
		//表示每个人开始工作的时间 
		for(int i = 1; i <= n; i++)
		{
			cin >> x;
			num[x + 1]++;
		}
		//二分答案 
		L = 0 , R = n , ans = -1;
		while( L <= R)
		{
			int mid = L + R >> 1;
			if(check(mid))
			{
				ans = mid;
				R = mid - 1;
			}
			else
				L = mid + 1;
		}
		
		if(ans == -1)
			cout << "No Solution\n";
		else
			cout << ans << endl;
	}

	return 0;
}

http://ybt.ssoier.cn:8088/problem_show.php?pid=1509

#include <bits/stdc++.h>
using namespace std;
const int N = 5e4 + 10;
const int INF = 0x3f3f3f3f;

int n;
int u , v , w , maxx;
vector<pair<int,int> > vc[N];
int dis[N];
bool vis[N];
void spfa()//求最长路！！！ 
{
	memset(dis, -INF, sizeof(dis));
	dis[0] = 0;
	vis[0] = 1;//表示当前点是否在队列中 
	queue<int> q;
	q.push(0);
	
	while(!q.empty())
	{
		int u = q.front();
		q.pop();
		vis[u] = 0;
		for(int i = 0; i < vc[u].size(); i++)
		{
			int v = vc[u][i].first , w = vc[u][i].second;
			if(dis[v] < dis[u] + w)
			{
				dis[v] = dis[u] +w;
				if(!vis[v]) 
				{
					q.push(v);	
					vis[v] = 1;
				}
			}	
		} 
	}
}

int main()
{
	cin >> n;
	for(int i = 1; i <= n; i++)
	{
		cin >> u >> v >> w;
		u++ , v++;//整体右移 
		//sum[v] - sum[u - 1] >= w
		vc[u - 1].push_back({v , w});
		maxx = max(maxx , v);
	}
	
	//隐藏不等式 sum[i] - sum[i - 1] >= 0     sum[i - 1] - sum[i] >= -1
	for(int i = 1; i <= maxx; i++)
	{
		vc[i - 1].push_back({i , 0});	
		vc[i].push_back({i - 1, -1});	
	} 
	spfa();
	cout << dis[maxx];
	return 0;
}

#include<iostream>
using amespace std;
int vera(int x,int y){
	return x+y;
}
int main(){
	int a=1,b=2;
	cout<<vera(a,b);
	return 0;
}

#include<bits/stdc++.h>
/*使用iostream库
导入cin和cout函数*/
using namespace std;
/*获取命名空间*/
int main(){//主函数
    int a,b;//定义整数变量
    cin>>a>>b;//输入数据
    cout<<a+b<<endl;//计算并输出数据

    return 0;//结束主函数
}

#include<bits/stdc++.h>
using namespace std;
int main(){
	long long a,b;
	cin>>a>>b;
	cout<<a+b;
}

#include<bits/stdc++.h> using namespace std; const int N=1e3+10; int fx(int x,int y){ return x+y; } int main() { int a=1,b=2; cin>>a>>b; cout<<fx(a,b); return 0; }

#include<bits/stdc++.h> using namespace std; const int N=1e3+10; int fx(int x,int y){ return x+y; } int main() { int a=1,b=2; cin>>a>>b; cout<<fx(a,b); return 0; }

#include <stdio.h> #include using namespace std; int main() { int a,b; cin >> a >> b; cout << a+b << endl; }

#include<bits/stdc++.h>
using namespace std;
int main(){
int a, b;
cin >> a >> b;
cout << a + b << endl;
return 0;
}

#include

using namespace std;

int main()

{

int a;

int b;

cin>>a>>b;

cout<<a+b;

return 0;

}