2 条题解

  • 1
    @ 2025-5-17 20:27:09
    
    #include <iostream>
    #include <cstring>
    #include <algorithm>
    using namespace std;
    
    const int N = 20;
    const int INF = 0x3f3f3f3f;
    int f[1<<N][N], weight[N][N];
    
    int main() {
        int n;
        cin >> n;
        for(int i = 0; i < n; i++)
            for(int j = 0; j < n; j++)
                cin >> weight[i][j];
        
        memset(f, 0x3f, sizeof(f));
        f[1][0] = 0; // 初始状态:只访问过0号点
        
        for(int mask = 0; mask < (1<<n); mask++) {
            for(int j = 0; j < n; j++) {
                if((mask >> j) & 1) { // j必须在mask中
                    for(int k = 0; k < n; k++) {
                        if(!((mask >> k) & 1)) { // k不能在mask中
                            f[mask|(1<<k)][k] = min(f[mask|(1<<k)][k], f[mask][j] + weight[j][k]);
                        }
                    }
                }
            }
        }
        
        cout << f[(1<<n)-1][n-1] << endl;
        return 0;
    }
    
    
    • @ 2025-5-18 21:13:21

      整治题解区. 现在的题解就是这样吗?

  • 1
    @ 2025-4-26 18:30:56

    #include #include using namespace std; int n, x; struct node { int int find(int num) { int l = 0, r = n-1; while (l <= r) { int mid = (l + r) / 2; if (num == a[mid].num) return a[mid].id; else if (num < a[mid].num) r = mid - 1; else l = mid + 1; } return -1; } bool cmp(node x, node y) { return x.num < y.num; } int main() { cin >> n; for (int i = 0; i < n; i++) { cin >> a[i].num; a[i].id = i+1; } sort (a, a + n,cmp); cin >> x; for (int i = 0; i < n; i++) { cout << a[i].num << " "; } cout << endl; int findnum = find(x); if(findnum == -1) cout << "吃饱喝足"; else cout << findnum << endl; }

    • 1

    信息

    ID
    4
    时间
    5000ms
    内存
    128MiB
    难度
    3
    标签
    递交数
    153
    已通过
    87
    上传者