5 条题解

  • 3
    @ 2025-7-30 14:15:49

    0分代码100Ac代码,已验证,放心复制↓

    #include <iostream>
    using namespace std;
    int main()
    {
    	int a;
    	cin >> a;
    	if(90<=a && a<=100)
    		cout << "A";
    	else if(80<=a && a<=89)
    		cout << "B";
    	else if(70<=a && a<=79)
    		cout << "C";
    	else if(60<=a && a<=69)
    		cout << "D";
    	else if(a<60)
    		cout << "E";
    	
        return 0;
    }
    
    • 1
      @ 2026-1-26 15:12:52
      #include <iostream>
      using namespace std;
      int a;
      int main()
      {
          cin >> a;
          if (a >= 90)
              cout << 'A';
          else if (a >= 80)
              cout << 'B';
          else if (a >= 70)
              cout << 'C';
          else if (a >= 60)
              cout << 'D';
          else
              cout << 'E';
          return 0;
      }
      • 0
        @ 2025-4-20 12:10:44

        最难的代码 最简洁的代码

        #include<iostream>
        using namespace std;
        int main ()
        {
        	int a;
        	cin >> a;
        	if(a>=90)
        	{
        		cout << "A";
        	}
        	
        	if(a>=80&a<90)
        	{
        		cout << "B";
        	}
        	if(a>=70&a<80)
        	{
        		cout << "C";
        	 } 
        	 if(a>=60&a<70)
        	{
        		cout << "D";
        	}
        	if(a<60)
        	{
        		cout << "E";
        	}
        }
        
        
        • -1
          @ 2025-3-11 13:26:46
          #include <queue>
          #include <math.h>
          #include <stack>
          #include <stdio.h>
          #include <iostream>
          #include <vector>
          #include <iomanip>
          #include <string.h>
          #include <algorithm>
          using namespace std;
          #define elif else if
          #define int long long
          #define float double
          #define N 30000010
          #define INF 0xc00000fd
          #define scf scanf
          #define ptf printf
          #define gtc getchar
          #define ptc putchar
          #define psp ptc(' ')
          #define pel ptc('\n')
          #define pzr ptc('0')
          #define fin for(int i = 1; i <= n; i++)
          #define fim for(int i = 1; i <= m; i++)
          #define fjn for(int j = 1; j <= n; j++)
          #define fjm for(int j = 1; j <= m; j++)
          #define rai fin	a[i] = read()
          #define wct write(cnt)
          #define pct print(cnt)
          #define was write(ans)
          #define pas print(ans)
          queue<int> Q;
          stack<int> S;
          vector<int> V;
          inline int wei(int n){
          	int cnt = 0;
          	while(n > 0){
          		n /= 10;
          		cnt++;
          	}
          	return cnt;
          }
          inline bool isPrime(int n){
          	if(n < 2)
          		return 0;
          	for(int i = 2; i * i <= n; ++i)
          		if(n % i == 0)
          			return 0;
          	return 1;
          }
          inline int read(string n){
          	int x = 0, f = 1;
          	ptf("%s", n.c_str());
          	char c = gtc();
          	while(c < '0'  ||  c > '9'){
          		if(c == '-')
          			f = -1;
          		c = gtc();
          	}
          	while(c >= '0'  &&  c <= '9'){
          		x = x * 10 + c - 48;
          		c = gtc();
          	}
          	return x * f;
          }
          inline float input(string n){
          	float x = 0, f = 1, x2 = 0, cnt = 0, i = 0;
          	ptf("%s", n.c_str());
          	char c = gtc();
          	while(c < '0'  ||  c > '9'){
          		if(c == '-')
          			f = -1;
          		c = gtc();
          	}
          	while(c >= '0'  &&  c <= '9'){
          		x = x * 10 + c - 48;
          		c = gtc();
          	}
          	c = gtc();
          	while(c >= '0'  &&  c <= '9'){
          		x2 = x2 * 10 + c - 48;
          		cnt++;
          		c = gtc();
          	}
          	for(; i < cnt; i++)
          		x2 /= 10.0;
          	return (x + x2) * f;
          }
          inline void write(int n) {
              if(n < 0){
                  ptc('-');
                  n = -n;
              }
              if(n > 9)
          		write(n / 10);
              ptc(n % 10 + '0');
          	return;
          }
          inline void print(int n, float m){
          	write(m);
          	m -= (int)m;
          	ptc('.');
          	int cnt = 0;
          	while(m - (int)m && n - cnt){
          		m *= 10;
          		ptc((int)m % 10 + '0');
          		cnt++;
          	}
          	n -= cnt;
          	fin
          		ptc('0');
          	return;
          }
          #define input() input("")
          #define read() read("")
          int n = read();
          char c;
          inline void Main(){
          	if(n > 90)
          		c = 'A';
          	elif(n >= 80)
          		c = 'B';
          	elif(n >= 70)
          		c = 'C';
          	elif(n >= 60)
          		c = 'D';
          	else
          		c = 'E';
          	ptc(c);
          	return;
          }
          signed main(signed argc, char **argv){
          	Main();
          	pel;
          	return 0;
          }
          
          • -4
            @ 2022-1-21 23:27:19
            #include <iostream>
            using namespace std;
            int main(){
                int n;
                cin>>n;
                if(n>=90)
                cout<<"A";
                else if(n>=80)
                    cout<<"B";
                else if(n>=70)
                    cout<<"C";
                else if(n>=60)
                    cout<<"D";
                else    
                    cout<<"E";
                return 0;
            }
            • 1

            信息

            ID
            854
            时间
            1000ms
            内存
            128MiB
            难度
            2
            标签
            递交数
            141
            已通过
            82
            上传者