#include<bits/stdc++.h> using namespace std; int main(){ int x; cin>>x; cout<<x<<" "<<10*x; }

刚做出一道特别难（对于我来说）的题，来一道简单的题放松一下。

#include <bits/stdc++.h>
using namespace std;
int main(){
	int n;
        cin>>n;
	cout<<n<<' '<<n*10;
	return 0;
}

GCC

#include <stdio.h>
int n;
int main(){
    scanf("%d", &n);
    printf("%d %d\n", n, n * 10);
}

#include<bits/stdc++.h>

using namespace std;

int main(){

int x;
cin>>x;
cout<<x<<" "<<x*10;
return 0;

}

#include

#include

#include

using namespace std;

int main()

{

int x;
cin>>x;
cout<<x<<" "<<x*10;
return 0;

}

1. #include<bits/stdc++.h>
using namespace std;
#define LL long long
const int N = 1e5 + 10;
const int INF = 0x3f3f3f3f;
int x;
int main()
{
    cin >> x;
    cout << x << " " << x * 10;
	return 0;
}
//菜鸟驿站
//老六专属

using namespace std;
int main(){
	int x;
	cin>>x;
	cout<<x<<" "<<x*10;
}

#include<bits/stdc++.h>
using namespace std;
int main(){
	int x;
	cin>>x;
	cout<<x<<" "<<x*10;
}

#include using namespace std; int main () { long long x; cin>>x; cout<<x<<" "<<10*x; return 0 ; }

#include<cstdio>
main()
{
	int n;
	std::scanf("%d",&n);
	std::printf("%d %d",n,n*10);
}

#include<iostream>
using namespace std;
int main()
{
	int x;
	cin>>x;
	long long ans=x*10;
	cout<<x<<" "<<ans;
	return 0;
}