#include<bits/stdc++.h>
using namespace std;
int main()
{
int n,m,a,b,c,s2,s3,i;double s1;
cin>>a>>m>>n;
s1=m;
for(i=1;i<=n;i=i+1)
{
s1=s1*(1+a*1.0/100);
}
s2=floor(s1);
cout<<s2;
}

#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
double r,m,y;
int main()
{
	cin >> r >> m >> y;
	r = (100 + r) / 100.0;
	for (int i = 1;i <= y;i++)
		m *= r;
	cout << fixed << setprecision(0) << (int)m;
	return 0;
}

#include using namespace std; int main() { int R, M, Y; cin >> R >> M >> Y; double money = M; for (int i = 0; i < Y; ++i) { money = money * (1 + R / 100.0); } cout << (int)money; return 0; }

#include <iostream>
#include <bits/stdc++.h>
using namespace std;
const int N=34354344;
long double x,k,y;
int main()
{
	cin>>x>>k>>y;
	x=1+x/100;
	for(int i=1;i<=y;i++)
	{
		k=k*x;
	}
	cout<<(int)k;
	return 0;
}

#include <iostream>
#include <bits/stdc++.h>
using namespace std;
const int N=1e7+10;
const int INF=0x3f3f3f3f;
long double r,n,y;
int main()
{
	cin>>r>>n>>y;
	r=1+r/100;
	for(int i=1;i<=y;i++)
	{
		n=n*r;
	}
	cout<<(int)n;
	return 0;
}

这题有点问题，当数字大一点，答案就是负数（double溢出），输出原本正确的正整数会判定为错

#include<bits/stdc++.h>
using namespace std;
int main()
{
int n,m,a,b,c,s2,s3,i;double s1;
cin>>a>>m>>n;
s1=m;
for(i=1;i<=n;i=i+1)
{
s1=s1*(1+a*1.0/100);
}
s2=floor(s1);
cout<<s2;
}

#include<bits/stdc++.h>

using namespace std;

int main()
{
    int n,m,a,b,c,s2,s3,i;double s1;
    cin>>a>>m>>n;

    s1=m;

    for(i=1;i<=n;i=i+1)
    {
        s1=s1*(1+a*1.0/100);
    }

    s2=floor(s1);
    cout<<s2;
}

#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 10;
const int INF = 0x3f3f3f3f;
int main(){
	int r,y;
	double m;
	cin >> r >> m >> y;
	long double x = 1 + r / 100.0;
	for(int i = 1;i <= y;i++){
		m = m * x;
	}
	cout << int(m);
	return 0;
	}

#include <iostream>
#include <stack>
#include <cmath>
#include <vector>
#include <string.h>
#include <queue>
#include <stdio.h>
#include <iomanip>
#include <cstdio>
#include <algorithm>
#define int long long
using namespace std;
const int N = 1e5 + 10;
const int INF = 0x3f3f3f3f;
signed main()
{
	double f, x, y;
	cin >> f >> x >> y;
	double l = 1.00 + f / 100;
	for(int i = 1; i <= y; i++)
	{
		x *= l;
	}
	cout << signed(x) << endl;
	return 0;
}

数据还可以让它过

#include <stdio.h>

#include

#include <math.h>

#include

#include

#include

#include

using namespace std;

int main()

{

double m,y,r;

cin>>r>>m>>y;

r=1+r/100;

for(int i=1;i<=y;i++)

{

	m*=r;

}

cout<<(int)m<<endl;

return 0;

}

/crl(陈儒乐)/

#include<bits/stdc++.h>//网上查到的万能头//

using namespace std;

int main()

{

double m,y,r;

cin >> r >> m >> y;

r = 1 + r/100;

for(int i = 1;i <= y;i++)

    m *= r;

cout << (int)m << endl;

return 0;    

}

#include<iostream>
#include<cstdio>
#include<cmath>
using namespace std;
int main()
{
    int n,m,a,b,c,s2,s3,i;double s1;
    cin>>a>>m>>n;
    s1=m;
    for(i=1;i<=n;i=i+1)
    {
    s1=s1*(1+a*1.0/100);
    }
    s2=floor(s1);
    cout<<s2;
}

#include <iostream>
#include <math.h>
#include <iomanip>
using namespace std;
#define LL Long Long
const int N=1e5+10;
const int INF=0x3f3f3f3f;
int main() 
{
    int R,M,Y;
    cin >> R >> M >> Y;
    int sum = 0;
    int R (0≤R≤20)
    int M (100≤M≤1,000,000)
    int Y (0≤Y≤400)
    cout << R << M << Y << endl;
}```

#include<iostream>
#include<cstdio>
#include<cmath>
using namespace std;
int main()
{
int n,m,a,b,c,s2,s3,i;double s1;
cin>>a>>m>>n;
s1=m;
for(i=1;i<=n;i=i+1)
{
s1=s1*(1+a*1.0/100);
}
s2=floor(s1);
cout<<s2;
}