#include <stdio.h>
#include <iostream>
using namespace std;
int main()
{
	int n,a,b=-1,c=1001;
	cin>>n;
	for(int i=1;i<=n;i++)
	{
		cin>>a;
		if(b<a)
		{
			b=a;	
		}
		if(c>a)
		{
			c=a;
		}
	}
	cout<<b-c;
}

#include <queue>
#include <math.h>
#include <stack>
#include <stdio.h>
#include <iostream>
#include <vector>
#include <iomanip>
#include <string.h>
#include <algorithm>
#include <bitset>
#include <cctype>
#include <cerrno>
#include <clocale>
#include <complex>
#include <cstdlib>
#include <ctime>
#include <deque>
#include <exception>
#include <fstream>
#include <functional>
#include <limits>
#include <list>
#include <map>
#include <ios>
#include <iosfwd>
#include <set>
#include <sstream>
#include <stdexcept>
#include <streambuf>
#include <utility>
#include <cwchar>
#include <cwctype>
using namespace std;
#define int long long
#define void inline void
queue<int> Q;
stack<int> S;
vector<int> V;
#ifndef SOMETHING_H
#define SOMETHING_H
#endif
inline int read(){
	int x = 0, f = 1;
	char c = getchar();
	while(c < '0'  ||  c > '9'){
		if(c == '-')
			f = -1;
		c = getchar();
	}
	while(c >= '0'  &&  c <= '9'){
		x = x * 10 + c - 48;
		c = getchar();
	}
	return x * f;
}
int n, a[30000001], maxn = -2100000000, minn = 2100000000;
void Main(){
	n = read();
	for(int i = 1; i <= n; i++)
		a[i] = read();
	for(int i = 1; i <= n; i++){
		if(a[i] > maxn)
			maxn = a[i];
		if(a[i] < minn)
			minn = a[i];
	}
	printf("%lld\n", maxn - minn);
	return;
}
signed main(){
	Main();
	return 0;
}

#include<bits/stdc++.h> using namespace std; int main() { int a,b,max = -1,min = 999999, ans; //gfhghfdhbhd cin >> a; for(int i = 1;i <= a ;i++){ cin >> b; if(b > max) max = b; if(b < min) min = b; } cout << max - min; return 0; }

#include<bits/stdc++.h> using namespace std; int main() { int n,x,m=-1000,m1=1000; cin>>n; for(int i=1; i<=n; i++) { cin>>x; m=max(m,x); m1=min(m1,x); } cout<<m-m1; return 0; }

#include <stdio.h> #include using namespace std; int n,a,maxx=-1000,minn=1000; int main(){ cin >> n; for( int i=1; i<=n ; i++){ cin >> a; maxx = max(a,maxx); minn= min(a, minn); } cout << maxx-minn;

1. }

/**************************************************************/
#include
using namespace std;
long long n,x,maxn=-1000,minn=1000;
int main(){
	cin>>n;
	for(int i=1;i<=n;i++){
		cin>>x;
		maxn=max(maxn,x);
		minn=min(minn,x);
	}
	cout<<maxn-minn;
	return 0;
}

水。。。 AC代码:

#include<iostream>
using namespace std;
long long n,x,maxn=-1000,minn=1000;
int main(){
	cin>>n;
	for(int i=1;i<=n;i++){
		cin>>x;
		maxn=max(maxn,x);
		minn=min(minn,x);
	}
	cout<<maxn-minn;
	return 0;
}

点个赞吧！

#include <stdio.h>
#include <iostream>
using namespace std;
int main()
{
	int n,a,b=-1,c=1001;
	cin>>n;
	for(int i=1;i<=n;i++)
	{
		cin>>a;
		if(b<a)
		{
			b=a;	
		}
		if(c>a)
		{
			c=a;
		}
	}
	cout<<b-c;
}

#include<iostream>
using namespace std;
int main()
{
    int n,a[1001];
    int min=9999,max=0;
    int i;
    cin>>n;
    for(i=1; i<=n; i++)
    {
        cin>>a[i];
        if(a[i]>max)
            max=a[i];
        if(a[i]<min)
            min=a[i];
    }

    cout<<max-min<<endl;
    return 0;
}

//#include <bits/stdc++.h> 
#include <iostream>
#include <stdio.h>
#include <math.h>
#include <iomanip>
using namespace std;
const int N = 1e5 + 10;
const int INF = 0x3f3f3f3f;
int n , a , x , d , cha;
int main()
{
	cin >> n;
	for( int i = 1 ; i <= n ; i++ )
	{
		cin >> a;
		if( i == 1 )
		{
			d = a;
			x = a;
			continue;
		}
		if( a < x )
		{
			x = a;
		}
		if( a > d )
		{
			d = a;
		}
	}
	cha = d - x;
	cout << cha; 
    return 0;
}

用的数组+for做的

#include<bits/stdc++.h>
using namespace std;
int main(){
	int n=0,i=1;
	cin>>n;
	int a[n+1];
	for(int i=1;i<=n;i++){
		cin>>a[i];
	}
	int max=a[1],min=a[1];
	for(i=1;i<=n;i++){
		if(a[i]>max){
			max=a[i];
		}
		if(a[i]<min){
			min=a[i];
		}
	}
	cout<<max-min;
	return 0;
}

#include using namespace std; long long n,x,maxn=-1000,minn=1000; int main(){ cin>>n; for(int i=1;i<=n;i++){ cin>>x; maxn=max(maxn,x); minn=min(minn,x); } cout<<maxn-minn; return 0; }

本来想用冷门词unsigned解这道题的，结果它丝毫不争气，无奈用回int 终于知道unsigned为什么冷门了。。 各位大佬如果知道用它怎么解，请告诉我吧！🎉️

AC代码：

#include<stdio.h>
#include<iostream>
#include<math.h>
using namespace std;
 int a;
 int n,maxx=0,minx=100000000;
int main()
{
	cin>>n;
	for(int i=1;i<=n;i+=1)
	{
		cin>>a;
		if(a<0)
		{
			continue;
		}
		maxx=max(maxx,a);
		minx=min(minx,a);
	}
	cout<<maxx-minx;
}

#include <iostream>
#include <stack>
#include <cmath>
#include <vector>
#include <string.h>
#include <queue>
#include <stdio.h>
#include <iomanip>
#include <cstdio>
#include <algorithm>
#define int long long
using namespace std;
const int N = 1e5 + 10;
const int INF = 0x3f3f3f3f;
signed main()
{
	int n;
	cin >> n;
	int maxn = -INF, minn = INF;
	for(int i = 1; i <= n; i++)
	{
		int x;
		cin >> x;
		maxn = max(maxn, x);
		minn = min(minn, x);
	}
	cout << maxn - minn  << endl;
	return 0;
}

嗯……

#include

using namespace std;

int main() { int n;

int a; 

int max =- 1;

int i;

int min = 1001;

cin >> n;

for (i = 1; i <= n; i ++)
{	
	cin >> a;

	if(a > max)
	{	
		
		max = a;
       
    }

	if(a < min)
	{
	
		min = a; 

    }

}

cout << max - min;

return 0;

}

#include <stdio.h>
#include <iostream>
using namespace std;
int main()
{
	int n,a,b=-1,c=1001;
	cin>>n;
	for(int i=1;i<=n;i++)
	{
		cin>>a;
		if(b<a)
		{
			b=a;	
		}
		if(c>a)
		{
			c=a;
		}
	}
	cout<<b-c;
}

水题 #include《~~~~iostream》 using namespace std; int n,x,_max=-10000,_min=10000; int main(){ cin>>n; for(int i=1;i<=n;i++){ cin>>x; _max=max(_max,x); _min=min(_min,x); } cout<<_max-_min; } 求赞